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20y^2-34y+6=0
a = 20; b = -34; c = +6;
Δ = b2-4ac
Δ = -342-4·20·6
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-26}{2*20}=\frac{8}{40} =1/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+26}{2*20}=\frac{60}{40} =1+1/2 $
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